Screenshot 2020-05-17 at 14.04.54

We know that the graph should be entirely above (or on) the x-axis, since anything squared is always non-negative, so we can discount (a). Further, the value of \sin is bounded above by 1, and thus so too is the value of y, so we can ignore (c). To see that the answer is (b), we note that \sqrt{x} is not a linear function, and so the period of \sin(\sqrt{x}) should increase with time (since the square root of x grows slower and slower the larger x gets).

(I think question E is posted already here.)

Quality Math Aptitude as well as Front End Quality Assurance Testing. Is it too much to ask for both??? Tim does not think so. :call_me_hand: :call_me_hand: :call_me_hand: :call_me_hand: :call_me_hand: :call_me_hand: :call_me_hand: :call_me_hand: :call_me_hand: :call_me_hand:

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