C3 2017 1 Edexcel

1

We have:

\begin{align*}\frac {4x} {x^2 - 9} - \frac 2 {x + 3} & = \frac {4x}{(x + 3)(x-3)} - \frac 2 {x + 3} \\ & = \frac {4x - 2(x - 3)} {(x + 3)(x - 3)} \\ & = \frac {2(x + 3)} {(x - 3)(x + 3)} \\ & = \frac 2 {x - 3}\end{align*}

:astonished: